SOLUTION: Please help : the sum of the squares of four consecutive integers is 630. Find the intergers.

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Question 969590: Please help :
the sum of the squares of four consecutive integers is 630. Find the intergers.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the squares of four consecutive integers is 630. Find the intergers.
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The hard way:
n^2 + (n+1)^2 + (n+2)^2 + (n+3)^2 = 630
4n^2 + 12n + 14 = 630
4n^2 + 12n - 616 = 0
n = 11
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The easy way:
630/4 = 157.5
sqrt%28157.5%29 =~ 12.5, the center, 2 integers below, 2 above.
--> 11, 12, 13 & 14