SOLUTION: Could you please help me with this: Twice the width of a rectangle is 3m more than the length. If the area of the rectangle is {209m^2}, find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: Could you please help me with this: Twice the width of a rectangle is 3m more than the length. If the area of the rectangle is {209m^2}, find the dimensions of the rectangle.       Log On


   

Question 969589: Could you please help me with this:
Twice the width of a rectangle is 3m more than the length. If the area of the rectangle is {209m^2}, find the dimensions of the rectangle.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
W=width; L=length=2W-3m; A=Area=209m^2
.
WL=A Substitute for L.
W%282W-3m%29=209m%5E2
2W%5E2-3W=209 Subtract 209 from each side.
2W%5E2-3W-209=0 Divide each side by 2.
W%5E2-1.5W-104.5=0
%28W-11%29%28W%2B9.5%29=0
W-11=0 or W%2B9.5=0
W=11 or W=9.5
.
ANSWER 1: The width is 11 meters
.
L=2W-3m=2%2811m%29-3m=22m-3m=19m
.
ANSWER 2: The length is 19 meters.
.
CHECK:
.
LW=A
%2819m%29%2811m%29=209m%5E2
209m%5E2=209m%5E2