SOLUTION: I'm trying to solve a problem. I solved half of it, but I don't know how to continue.
This is the problem: "If the length of a rectangle is 1 foot less than twice its width and i
Algebra ->
Rectangles
-> SOLUTION: I'm trying to solve a problem. I solved half of it, but I don't know how to continue.
This is the problem: "If the length of a rectangle is 1 foot less than twice its width and i
Log On
Question 965533: I'm trying to solve a problem. I solved half of it, but I don't know how to continue.
This is the problem: "If the length of a rectangle is 1 foot less than twice its width and its perimeter is 34 feet, what is the length of the rectangle in feet?
You can put this solution on YOUR website! let x be the width(w), then length(l) is 2x-1
Perimeter(P) of a rectangle = 2l + 2w
34 = 2(2x-1) +2x
34 = 4x-2 +2x
6x = 36
x = 6 and
l = 2*6 -1 = 11
the length of the rectangle is 11 feet
