SOLUTION: the length of a rectangle is twice its width. if the perimeter of the rectangle is 64 ft, find its area

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Question 949093: the length of a rectangle is twice its width. if the perimeter of the rectangle is 64 ft, find its area
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
W=width; L=length=2W; P=perimeter=2(L+W)=64 ft; Area =L*W
P=2(L+W)
64 ft=2(L+W) Divide each side by 2
32 ft=L+W Substitute for L
32 ft=2W+W
32 ft=3W Divide each side by 3
(32/3)ft=W
Area =L*W Substitute for L
Area=2W*W
Area=2W%5E2
Area=2%2832ft%2F3%29%5E2=2%281024%2F9%29sq+ft=227.6 sq ft
ANSWER Area of the rectangle is 227.6 sq ft.