SOLUTION: The area of a rectangle is 55yds. squared, and the length of the rectangle is 4yds less than three times the width. Find the dimensions of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The area of a rectangle is 55yds. squared, and the length of the rectangle is 4yds less than three times the width. Find the dimensions of the rectangle.      Log On


   

Question 934588: The area of a rectangle is 55yds. squared, and the length of the rectangle is 4yds less than three times the width. Find the dimensions of the rectangle.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

L = 3w-4

A = Lw

(3w-4)w = 55 yd^2

3w^2 - 4w - 55 = 0  (tossing out negative solution for unit measure)

(3w+11)(w-5) = 0

w = 5 yd  and L = 11yd 3%285%29+-+4

And...checking

(11yd)(5yd) = 55yd^2