SOLUTION: if the area of a rectangle is 52 and perimeter is 34 and length=width*2+5 what is length and width

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Question 933379: if the area of a rectangle is 52 and perimeter is 34 and length=width*2+5 what is length and width
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if the area of a rectangle is 52 and perimeter is 34 and length=width*2+5 what is length and width
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Area = L*W = 52
Perimeter = 2L + 2W = 34 --> L + W = 17
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Try pairs of factors of 52 (there aren't many).
Find a pair with a sum of 17.