SOLUTION: The length of a rectangle is three times its width. If the perimeter of the rectangle is 64yd,find its area.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is three times its width. If the perimeter of the rectangle is 64yd,find its area.      Log On


   



Question 932115: The length of a rectangle is three times its width.
If the perimeter of the rectangle is
64yd,find its area.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
L=3W
For a rectangle,
P=2%28L%2BW%29=64
L%2BW=32
Substituting,
3W%2BW=32
4W=32
W=8
Then,
L=3%288%29
L=24
For a rectangle,
A=L%2AW
A=24%288%29
A=192yd%5E2