SOLUTION: given JKMN is a rectangle if m<NKM= x^2+4 and m<NKJ= x+30 find m<JKN my question was x^2+4=x+30

Algebra ->  Rectangles -> SOLUTION: given JKMN is a rectangle if m<NKM= x^2+4 and m<NKJ= x+30 find m<JKN my question was x^2+4=x+30       Log On


   

Question 931641: given JKMN is a rectangle
if m
my question was x^2+4=x+30
Found 2 solutions by Fombitz, MathLover1:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
If it's a rectangle, every angle is 90.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given JKMN is a rectangle; so all angles are 90 degrees
if m < NKM=+x%5E2%2B4=>+x%5E2%2B4=90..solve for x
+x%5E2=90-4
+x%5E2=86
+x=sqrt%2886%29
+x=9.273618495495704 exact solution (and, we will not need negative solution)
+x=9.27 approximate solution
and
m < NKJ=+x%2B30 => m < x%2B30=+90=> m < x=60