SOLUTION: The width of a rectangle is five times its lenghy. If the area of the rectangle is 45, then what is the perimeter of the rectangle? a) 3 b)9 c)15 d)18 e)36

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Question 927335: The width of a rectangle is five times its lenghy. If the area of the rectangle is 45, then what is the perimeter of the rectangle?
a) 3
b)9
c)15
d)18
e)36
Answer by srinivas.g(540) About Me  (Show Source):
You can put this solution on YOUR website!
Let length of rectangle be l
Width = 5 times the length
width = 5l
area = 45
length x width =45
l x 5l =45
+5l%5E2+=45
divide with 5 on both sides
+5+l%5E2%2F5=+45%2F5
+l%5E2+=9
square root on both sides
+sqrt%28l%5E2%29+=sqrt%289%29
l=3
width = 5x3 = 15
Perimeter = 2(length+width)
=2(3+15)
=2*18
=36
Result : Perimeter = 36