SOLUTION: The length of a rectangle is twice its width. If the area of the rectangle is 128 ft2 , find its perimeter.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is twice its width. If the area of the rectangle is 128 ft2 , find its perimeter.      Log On


   

Question 926473: The length of a rectangle is twice its width.
If the area of the rectangle is
128

ft2
, find its perimeter.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
You are told the that a rectangle has a Length that is twice its Width.
Let Width = W
Then Length = 2W
Area of a rectangle = Length+%2A+Width = 2W+%2A+W = 2W%5E2
Perimeter of a rectangle = 2%2AWidth++=+2%2ALength = 2W+%2B+2%2A2W = 2W+%2B4W = 6W
You are told the area is 128 square feet
128+=+2W%5E2
64+=+W%5E2
8+=+W
Perimeter+=+6W
Perimeter+=+6%2A8
Perimeter+=+48