SOLUTION: The length of a rectangle is(x+5) and its width is (x-3). Find the value of x if the perimeter of the rectangle is 40cm. (P=21+2w)

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is(x+5) and its width is (x-3). Find the value of x if the perimeter of the rectangle is 40cm. (P=21+2w)      Log On


   

Question 919705: The length of a rectangle is(x+5) and its width is (x-3). Find the value of x if the perimeter of the rectangle is 40cm. (P=21+2w)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

P = 2L + 2w

2(x+5) + 2(x-3) = 40cm

4x = 36

x = 9cm

L = 14cm 9%2B5  and w = 6cm 9-3

and...checking

P = 28cm + 12cm = 40cm