SOLUTION: The length of a rectangle is twice the width. The area is 38 square inches. a. Perimeter is = &#8730;48 b. You cannot calculate the perimeter with the given information. c. Pe

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Question 911671: The length of a rectangle is twice the width. The area is 38 square inches.
a. Perimeter is = √48
b. You cannot calculate the perimeter with the given information.
c. Perimeter is ≈ 6.93 inches
d. Perimeter is ≈ 29.4 inches

Found 2 solutions by ewatrrr, MathLover1:
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!

Hi,
.
A = Lw
(2w)w - 38in^2
2w^2 = 38
w^2 = 19
w = √19
L = 2√19
P = 6√19

Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is twice the width .
...eq.1
The area is .

find the perimeter :

and =>

..plug in

then => =>

so,

so, option . Perimeter is ≈ is closest one

SOLUTION: The length of a rectangle is twice the width. The area is 38 square inches. a. Perimeter is = &#8730;48 b. You cannot calculate the perimeter with the given information. c. Pe

SOLUTION: The length of a rectangle is twice the width. The area is 38 square inches. a. Perimeter is = √48 b. You cannot calculate the perimeter with the given information. c. Pe