SOLUTION: The perimeter of a rectangle is 40 feet. The length is three times long as the width. Let x = width of the rectangle. What is the width of the rectangle?

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 40 feet. The length is three times long as the width. Let x = width of the rectangle. What is the width of the rectangle?      Log On


   

Question 907987: The perimeter of a rectangle is 40 feet.

The length is three times long as the width.

Let x = width of the rectangle.

What is the width of the rectangle?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x is width, unknown.
y is length, unknown.
p is perimeter, known.
y=3x, from description.
Find x, the width.

2x%2B2y=p
2x%2B2%283x%29=p
2x%2B6x=p
8x=p
highlight%28x=p%2F8%29