SOLUTION: The length is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width. Find the length and width of the rectangle described.

Algebra ->  Rectangles -> SOLUTION: The length is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width. Find the length and width of the rectangle described.      Log On


   

Question 905908: The length is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width.
Find the length and width of the rectangle described.
Found 2 solutions by ewatrrr, 100601:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

 

Hi,

     .

L + w = 11

(3w-4) + w = 11

4w = 15

w = 15/4  Or 3.75units and L = 7.25 3%2A3.75+-+4

and...checking

sum = 11

Answer by 100601(6) About Me  (Show Source):
You can put this solution on YOUR website!
l= length in cm
w= width in cm


Keep in mind that you can substitute = for the word 'is' in word problems.
l=3w-4
Perimeter=2w+22
Perimeter=2l+2w


Substitute 2l+2w for the perimeter
2l+2w=2w+22
2l=22
l=11


Now find w by substitute 11 for l in the first equation.
11=3w-4
3w=15
w=5


Answer:
length- 11 cm
width- 5 cm