Question 896643: The length of a rectangle is
5
cm
longer than its width.
If the perimeter of the rectangle is
46
cm
, find its area.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! Easiest to find the length and width first, and then use them for area.
w for width, L for length, p for perimeter.
Assume p is known, k is known, and w and L unknowns.
 and  .
k=5 and p=46;
but staying completely in symbols, you first want to solve for w and L.
 .
-
-
-
Spend some time checking how those formulas look for w and L. See how they resemble each other but are not the same.
Remember, the question was, FIND AREA.
This means find  .
Using the formulas for L and w,
 -----The AREA, in symbolic form.
-
Now, just substitute the given values from the description to find value for the area.
 , square centimeters
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 5 cm longer than its width. If the perimeter of the rectangle is 46 cm, find its area.
Let width be W
Then length = W + 5
Since perimeter = 46, then: 2W + 2(W + 5) = 46
2W + 2W + 10 = 46
4W + 10 = 46
4W = 46 – 10
4W = 36
W, or width =  , or 9
Length: 9 + 5, or 14
Area: 9(14), or  sq cm
|
|
|
