SOLUTION: In a rectangle with perimeter 30 cm and area 56 cm, the longer sides length is one cm more than the shorter side.

Algebra ->  Rectangles -> SOLUTION: In a rectangle with perimeter 30 cm and area 56 cm, the longer sides length is one cm more than the shorter side.      Log On


   

Question 896598: In a rectangle with perimeter 30 cm and area 56 cm, the longer sides length is one cm more than the shorter side.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y=x+1 for sides x and y.

2x%2B2y=30
x%2By=15
x%2Bx%2B1=15
2x=14
highlight%28x=7%29
AND
x%28x%2B1%29=56 but we already found x; so this equation simply tells us what we already could find without being given this area.

Move on to find y.
highlight%28y=8%29.


You could have ignored the perimeter information and just used the area information along with the sides relationship to find the dimensions.