SOLUTION: The perimeter of a certain rectangle is 15 feet. The length of the rectangle is 5 feet longer than twice its width. Which of the following equations could you use to determine the

Algebra ->  Rectangles -> SOLUTION: The perimeter of a certain rectangle is 15 feet. The length of the rectangle is 5 feet longer than twice its width. Which of the following equations could you use to determine the       Log On


   

Question 896039: The perimeter of a certain rectangle is 15 feet. The length of the rectangle is 5 feet longer than twice its width. Which of the following equations could you use to determine the dimensions of the rectangle?
15 ft. = 2w + 2(2w + 5)
15 ft. = 4w + 5
15 ft. = 2w + 2(2w + 10)
15 ft. = 2(2w + 5)
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
P = 2L+ 2W
You're given P as 15
You're given L = 2W + 5


P = 2L + 2W
15 = 2L + 2W
15 = 2(2W+5) + 2W
15 = 4W+10 + 2W
15 = 6W + 10
5 = 6W
W = 5%2F6