SOLUTION: I would greatly appreciate some assistance in trying to solve a problem. I cannot draw the problem on here but I can describe it as it is very easy to replicate. There is a vertica

Algebra ->  Rectangles -> SOLUTION: I would greatly appreciate some assistance in trying to solve a problem. I cannot draw the problem on here but I can describe it as it is very easy to replicate. There is a vertica      Log On


   

Question 894416: I would greatly appreciate some assistance in trying to solve a problem. I cannot draw the problem on here but I can describe it as it is very easy to replicate. There is a vertical rectangle measuring 6.7cm on the bottom and 7.23ccm along the sides. Now, there is a half circle on top of the rectangle that has the same diameter as the base of the rectangle, 6.7cm. I need to find the perimeter of the rectangle and half circle together.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The diameter of your half-circle is 6.7 cm. The radius of your half-circle is 6.7%2F2 cm. The arc length of your half-circle is %281%2F2%29%282%2Api%2A%286.7%2F2%29%29.

You specified the perimeter of the half-circle and the rectangle together. You might really mean, the perimeter of the figure, and not as separate parts. If so, then you have just the arc length and THREE sides of the rectangle:

%282%287.23%29%2B6.7%29%2B%28pi%2A6.7%2F2%29 cm.