SOLUTION: The width of a rectangle is two inches longer than one-third of its length. Find the width and the length if the perimeter is 68 inches.

Algebra ->  Rectangles -> SOLUTION: The width of a rectangle is two inches longer than one-third of its length. Find the width and the length if the perimeter is 68 inches.       Log On


   

Question 891417: The width of a rectangle is two inches longer than one-third of its length. Find the width and the length if the perimeter is 68 inches.
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter = 2L + 2W
W = 1%2F3L + 2
Substitute the value of W from the second equation into the first
P = 2L + 2W
68 = 2L + 2(1%2F3L+2)
68 = 2L + 2%2F3L + 4
Subtract 4 from each side
64 = 22%2F3L
64 = 8%2F3L
Multiply each side by 3%2F8
24 = L
If the length is 24, the width is 1%2F3 of that + 2, or 10
24 + 24 + 10 + 10 = 68