SOLUTION: the length of a rectangle is 3 feet less than twice the width. If the area of the rectangle is 54 ft^2, find the dimensions of the rectangle. Solve by using a quadratic equation

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Question 891321: the length of a rectangle is 3 feet less than twice the width. If the area of the rectangle is 54 ft^2, find the dimensions of the rectangle. Solve by using a quadratic equation
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w with
L length
L=-3+2w and wL=54

w%282w-3%29=54
w%5E2-3w-54=0
Factorable? 54=27*2=3*3*3*2=9*6
%28w%2B6%29%28w-9%29=0
highlight%28w=9%29
-
highlight%28L=2%2A9-3%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

the length of a rectangle is 3 feet less than twice the width. If the area of the rectangle is 54 ft^2, find the dimensions of the rectangle. Solve by using a quadratic equation


Width:   highlight_green%286%29%29 ft

Length:  highlight_green%289%29%29 ft

You can do the check!! 



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