SOLUTION: please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.

Algebra ->  Rectangles -> SOLUTION: please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.       Log On


   



Question 890730: please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
VARIABLES: w for width, L for length


TRANSLATE: L=-8+3w, 2w+2L=64.

SIMPLIFY AND SUBSTITUTE:
w+L=32;
w+(3w-8)=32

SOLVE FOR w FIRST:
4w-8=32
4w=24
w=6

Finish finding L:
L=3w-8
L=3*6-8
L=18-8
L=10

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

please help me solve : the perimeter of a rectangle is 64 meters. the length is eight meters less than three times the width.

Width: highlight_green%28highlight_green%2810%29%29 m
Length: highlight_green%28highlight_green%2822%29%29 m
You can do the check!!
If you need a complete and detailed solution, let me know!!
Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
Further help is available, online or in-person, for a fee, obviously.
For FREE info and answers to questions about the ASVAB exam, the NYS 3 – 8 city/state wide exams,GENERAL
MATH and HOMEWORK QUESTIONS, or MATH QUESTIONS related to the Regents Integrated Algebra,
Regents Geometry, Regents Algebra 2/Trigonometry, SHSAT, COOP/HSPT/TACHS, PSAT, SAT, ACT, SSAT/ISEE,
GRE, CLEP, and the TASC/GED, you can visit: http://asvabstudyzone.freeforums.net/.