SOLUTION: two rectangles have an area of 630 cm square each. the difference in the lengths of the rectangle is 5 cm while that in their widths is 3 cm. find the dimension of the two rectangl

Algebra ->  Rectangles -> SOLUTION: two rectangles have an area of 630 cm square each. the difference in the lengths of the rectangle is 5 cm while that in their widths is 3 cm. find the dimension of the two rectangl      Log On


   

Question 889713: two rectangles have an area of 630 cm square each. the difference in the lengths of the rectangle is 5 cm while that in their widths is 3 cm. find the dimension of the two rectangles.
Answer by lwsshak3(11628) About Me  (Show Source):
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two rectangles have an area of 630 cm square each. the difference in the lengths of the rectangle is 5 cm while that in their widths is 3 cm. find the dimension of the two rectangles.
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let x=length of 1st triangle
let y=width of 1st triangle
let x-5=length of 2nd triangle
let y+3=width of 2nd triangle
..
length*width=area
xy=630
y=630/x
..
%28x-5%29%28y%2B3%29=630
%28x-5%29%28630%2Fx%2B3%29=630
%28x-5%29%28630%2B3x%29%2Fx=630
%28x-5%29%283x%2B630%29=630x
3x%5E2%2B615x-3150=630x
3x%5E2-15x-3150=0
x^2-5x-1050=0
(x+30)(x-35)=0
x=-30 (reject)
or
x=35
y=630/x=18
x-5=30
y+3=21
..
dimension of 1st rectangle=35 by 18 cm
dimension of 2nd rectangle=30 by 21 cm