SOLUTION: A steel wire of 28m is bent to form a rectangle with an area of 46 m2. Calculate the breadth and length of the rectangle.

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Question 889128: A steel wire of 28m is bent to form a rectangle with an area of 46 m2. Calculate the breadth and length of the rectangle.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2%28L%2BW%29=28
L%2BW=14
.
.
L%2AW=46
Substituting from above,
%2814-W%29W=46
14W-W%5E2=46
W%5E2-14W%2B46=0
%28W%5E2-14W%2B49%29%2B46-49=0
%28W-7%29%5E2-3=0
%28W-7%29%5E2=3
W-7=0+%2B-+sqrt%283%29
W=7+%2B-+sqrt%283%29
Then,
L=14-%287+%2B-sqrt%283%29%29
L=7+%2B-+sqrt%283%29 <--- In this case it should be -/+ not +/- but I don't have that symbol.
So, the dimensions of the rectangle are,
7%2Bsqrt%283%29 X 7-sqrt%283%29