SOLUTION: Given a square with two vertices of one side located at (-5, -3) and (-5, 12), in square units what is its area?

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Question 887330: Given a square with two vertices of one side located at (-5, -3) and (-5, 12), in square units what is its area?
Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
To solve this problem we need to use the distance formula which is d=sqrt%28%28x1-x2%29%5E2%2B%28y1-y2%29%5E2%29

We also need to use the fact that in a square all sides of the length. We also know that the area of a rectangle(which a square is a special type of rectangle is) its length times its width. Since all sides of a square have the same length(stated above) the area becomes length times length. So all we need to do to find the area of this square is to find the length of the side(the distance between those two points) and square it.

So the area of the square is:

Area = (d=sqrt%28%28x1-x2%29%5E2%2B%28y1-y2%29%5E2%29)^2
=%28x1-x2%29%5E2%2B%28y1-y2%29%5E2
=%28-5-%28-5%29%29%5E2%2B%28-3-12%29%5E2
=0%5E2%2B%28-15%29%5E2
=225 square units