SOLUTION: a poster is designed so that its length will always be 4 inches more than its height. The height is x inches. The area of the poster (length times height) is y square inches. Write

Algebra ->  Rectangles -> SOLUTION: a poster is designed so that its length will always be 4 inches more than its height. The height is x inches. The area of the poster (length times height) is y square inches. Write      Log On


   



Question 885562: a poster is designed so that its length will always be 4 inches more than its height. The height is x inches. The area of the poster (length times height) is y square inches. Write an equation that best describes the word problem above
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Assign variables to everything you can unless already assigned in the description and write the numeric facts that the description indicates.

x = height
y = area
u = length (could be any other variable not yet assigned)
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u=4+x

The description can give you a relationship for all of these using formula for area: Length%2AHeight=Area;

Area, y=x%2Au, or y=x%28x%2B4%29, or if you want to solve the length equation for x, you can show y as a function of u.