SOLUTION: I havea Question that is really giving me a hard time. Please Help. Finf the length of each side of the rectangle so that it has a perimeter of 50. One side is 2x-5 and one side i

Algebra ->  Rectangles -> SOLUTION: I havea Question that is really giving me a hard time. Please Help. Finf the length of each side of the rectangle so that it has a perimeter of 50. One side is 2x-5 and one side i      Log On


   

Question 88509: I havea Question that is really giving me a hard time. Please Help.
Finf the length of each side of the rectangle so that it has a perimeter of 50. One side is 2x-5 and one side is x.
Found 2 solutions by Earlsdon, ptaylor:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the formula for the perimeter of a rectangle:
P+=+2L%2B2W where, L = length, W = width, and P = 50.
You are given that one side (let this side be L) is 2x-5 and the other side (let this side be W) is x. Substitute these for L and W into the formula and solve for x.
50+=+2%282x-5%29%2B2x
50+=+4x-10%2B2x
50+=+6x-10 Add 10 to both sides.
60+=+6x Divide both sides by 6.
10+=+x
So the lengths of the sides of the rectangle are:
Length = 2x-5 = 2(10)-5 = 20-5 = 15
Width = x = 10

Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
Let 2x-5 be the length
Then x is the width

Perimeter(P) equals two times the Length(L) plus two times the Width(W), or:
P=2L+2W Now we are told that:

50=2(2x-5)+2(x) get rid of parens
50=4x-10+2x add 10 to both sides
50+10=4x-10+10+2x collect like terms
60=6x divide both sides by 6
x=10-----------------width
2x-5=2*10-5=15------------------length
CK
50=2(15)+2(10)
50=30+20
50=50

Hope this helps---ptaylor