SOLUTION: The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 88 cm^2, what is the length of the diagonal?

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Question 884734: The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 88 cm^2, what is the length of the diagonal?
Answer by lwsshak3(11628) About Me  (Show Source):
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The width of a rectangle is 1 less than twice its length. If the area of the rectangle is 88 cm^2, what is the length of the diagonal?
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let x=length of rectangle
2x-1=width of rectangle
..
length*width=area
x(2x-1)=88
2x^2-x=88
2x^2-x-88=0
solve for x by quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=2, b=-1, c=-88
ans:
x=length≈6.89
width≈2*6.89-1≈12.78
diagonal≈√[(6.89)^2+(12.78)^2]≈√(47.47+163.33)≈√210.80≈14.52
length of the diagonal≈14.52 cm