SOLUTION: A rectangular piece of cardboard is 2 units longer than it is wide. From each of its corners a square piece 2 units on a side is cut out. The flaps are then turned up to form an op

Algebra ->  Rectangles -> SOLUTION: A rectangular piece of cardboard is 2 units longer than it is wide. From each of its corners a square piece 2 units on a side is cut out. The flaps are then turned up to form an op      Log On


   



Question 882755: A rectangular piece of cardboard is 2 units longer than it is wide. From each of its corners a square piece 2 units on a side is cut out. The flaps are then turned up to form an open box that has a volume of 70 cubic units. Find the length and width of the original piece of cardboard.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x, width
x+2, length
-
2 unit square removed from each corner;
flaps then turned to meet forming box.

Base surface, %28x-2%2A2%29%28%28x%2B2%29-2%2A2%29, be sure this line makes sense;
%28x-4%29%28x-2%29
x%5E2-6x%2B8

Height of this box is 2 units, so volume is 2%28x%5E2-6x%2B8%29;

The volume was given as 70 cubic units, so highlight_green%282x%5E2-12x%2B16=70%29.
Simplifyable to x%5E2-6x%2B8=35, and then
x%5E2-6x%2B8-35=0
highlight_green%28x%5E2-6x-27=0%29----this is FACTORABLE!

Factor the expression, pick the right (sensible) value for x, then compute x+2. Once all this, solution done.