SOLUTION: the lenght of a rectangle is 8 inches greater than its width find the width of the rectangle if it area is 105 square inches

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Question 880547: the lenght of a rectangle is 8 inches greater than its width find the width of the rectangle if it area is 105 square inches
Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L=8+w and wL=105.

w%28w%2B8%29=105
w%5E2%2B8w-105=0
%28w-7%29%28w%2B15%29=0
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Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
the lenght of a rectangle is 8 inches greater than its width find the width of the rectangle if it area is 105 square inches
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let x=width of rectangle
x+8=length of rectangle
width*length=area
x(x+8)=105
x^2+8x=105
x^2+8x-105=0
(x+15)(x-7)=0
x=-15 (reject)
or
x=7
width of rectangle=7 inches