SOLUTION: The perimeter of a rectangular painting is 128 cm. The width is 3 times the length. What are the length and width of the painting? I know the equation is 2L+2(3L)=128 but I don't

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangular painting is 128 cm. The width is 3 times the length. What are the length and width of the painting? I know the equation is 2L+2(3L)=128 but I don't       Log On


   

Question 877921: The perimeter of a rectangular painting is 128 cm. The width is 3 times the length. What are the length and width of the painting?
I know the equation is 2L+2(3L)=128 but I don't know what to do from there.
Thanks(:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
That looks right. Why be stuck?

w for width
L for length
w=3L
-
2w%2B2L=128
2%283L%29%2B2L=128
6L%2B2L=128
8L=128
L=128%2F8=%2864%2A2%29%2F8
highlight%28L=16%29
-
From given w=3L,
w=3%2A16=3%288%2B8%29=24%2B24=48
highlight%28w=48%29