SOLUTION: how do I solve? The perimeter of a football field is 440 yds. The width is 70 yds more than twice the length. what are the dimensions?

Algebra ->  Rectangles -> SOLUTION: how do I solve? The perimeter of a football field is 440 yds. The width is 70 yds more than twice the length. what are the dimensions?      Log On


   

Question 873924: how do I solve? The perimeter of a football field is 440 yds. The width is 70 yds more than twice the length. what are the dimensions?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
"The perimeter of a football field is 440 yds" ----> P = 440

"The width is 70 yds more than twice the length" ----> W = 2L + 70


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Perimeter of a rectangle

P = 2*(L+W)

440 = 2*(L+W) ... plug in the perimeter

440 = 2*(L + 2L + 70) ... plug in W = 2L + 70

I'll let you finish up.