SOLUTION: The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle is 26 cm squared, what is the rectangles dimensions?
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Question 862654: The length of a rectangle is 9 cm less than twice its width. If the area of the rectangle is 26 cm squared, what is the rectangles dimensions? Answer by ewatrrr(24785) (Show Source):
Hi
A = Lw
26cm^2 = (2w-9cm)w | length = 9 cm less than twice its width
2w^2 - 9w - 26 = 0
(2w -13)(w + 2) = 0 (Tossing out the negative solution for unit measure)
w = 13/2cm 0r 6.5cm and L = 4cm
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