Question 861656: The length of rectangle is 5 more than the width. If the area is 20 square units. What are the dimension of the rectangle?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! Very typical question about rectangle. I will solve this completely in symbols, generally.
L = length
w = width
k = a given constant.
p = perimeter, a given constant.
The description is as L=w+k, and perimeter, p is given.
This like the generalization, "the length of the rectangle is k more than the width."
Perimeter Equation:
 .
In general, p might or might not be a whole number, and it might or might not be an even number, so I will not immediately here divide both sides by 2.
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Use the formula for w to find the formula for L.
The description gave L=w+k, so now have  , and depending on the kind of form in which you want, can become 
 .
Naturally, substitute the given values to compute the values for L and w.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
The length of rectangle is 5 more than the width. If the area is 20 square units. What are the dimension of the rectangle?
Let width be W
Then length = W + 5
Therefore, W(W + 5) = 20
Use the quadratic equation formula to solve for W, or the width
Add 5 to that value to determine the value of the length
Then do a check!!
If you need a complete and detailed solution, let me know!!
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