SOLUTION: The length of a rectangle is 7 feet longer then twice the width, if the perimeter is 86 feet. Find the Length and Width of the rectangle

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Question 858986: The length of a rectangle is 7 feet longer then twice the width, if the perimeter is 86 feet. Find the Length and Width of the rectangle
Answer by Awesom3guy(31) About Me  (Show Source):
You can put this solution on YOUR website!
As a rectangle is bounded by two pairs of equal sides a and b, the formula for its perimeter is:
P+=+2a+%2B+2b.
Or
P+=+2L+%2B+2W
If we are talking about length and width.

The length of a rectangle is 7 feet longer then twice the width.
L+=+2W+%2B+7

Now we can plug 2W+%2B+7 in the place of L in the formula for perimeter and 86 for in the place of P.
86+=+2%282W+%2B+7%29+%2B+2W
Expand the bracket and collect like terms:
86+=+6W+%2B+14
72+=+6W
W+=+12
The width of the rectangle is 12 feet.

Finding length:
L+=+2W+%2B+7
L+=+2%2A12+%2B+7+=+31
Its length is 31 feet.
Now you want to check.
P+=+2L+%2B+2W
86+=+2%2A31+%2B+2%2A12
All good.