SOLUTION: the area of a rectangle is 3x^2+14x+15 square meters. this area is reduced by decreasing both the length and width by 3 meters. if the dimensions of the original rectangle are repr

Algebra ->  Rectangles -> SOLUTION: the area of a rectangle is 3x^2+14x+15 square meters. this area is reduced by decreasing both the length and width by 3 meters. if the dimensions of the original rectangle are repr      Log On


   



Question 849685: the area of a rectangle is 3x^2+14x+15 square meters. this area is reduced by decreasing both the length and width by 3 meters. if the dimensions of the original rectangle are represented by binomials with integral coefficients, find the area of the new rectangle.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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the area of a rectangle is 3x^2+14x+15 square meters. this area is reduced by decreasing both the length and width by 3 meters.
if the dimensions of the original rectangle are represented by binomials with integral coefficients, find the area of the new rectangle.
:
Find the original binomials which represent the original dimensions
3x^ + 14x + 15
Factors to
(3x + 9)(x + 5%2F3) = 0
therefore
3x = -9
x = -3
and
x = -5%2F3
Subtract 3 from both
x = -6
and
x = -14%2F3
multiply both sides by 3
3x = -14
FOIL the two factor obtained from this:
(x + 6)(3x + 14) = 0
3x^2 + 14x + 18x + 84 = 0
3x^2 + 32x + 84 = 0; the area of the new rectangle