SOLUTION: How do you find x when a rectangles sides are Length= x Width= x+13 And the area is 285cm^2 I get it set up to X(x+13) = 285cm^2 X^2 + 13x = 285cm^2

Algebra ->  Rectangles -> SOLUTION: How do you find x when a rectangles sides are Length= x Width= x+13 And the area is 285cm^2 I get it set up to X(x+13) = 285cm^2 X^2 + 13x = 285cm^2      Log On


   



Question 845911: How do you find x when a rectangles sides are
Length= x
Width= x+13
And the area is 285cm^2
I get it set up to
X(x+13) = 285cm^2
X^2 + 13x = 285cm^2

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The only mistake is the incorrect case-level for x. Otherwise, your steps are good. What is stopping your from continuing?

Is x%5E2%2B13x-285 factorable? If you believe so, then find the factorization. If you are not sure if factorable, use the general solution of a quadratic equation.

285=3%2A5%2A19. A value of 13 will not come from any of this.

General Solution:
D=13%5E2-4%28-285%29=169%2B1140=1309
Also D=1309=7%2A11%2A17, three prime factors.
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x=%28-13%2Bsqrt%28D%29%29%2F2
highlight%28x=%28-13%2Bsqrt%281309%29%29%2F2%29