SOLUTION: Find the area of a rectangle with a width of 3x-4 and a length of 7x+3.
This is what I have:{{{ (3x-4)^2(7x+3)^2)}}}
I worked it this way:
(3x)^2-(4)^2 + (7x)^
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Rectangles
-> SOLUTION: Find the area of a rectangle with a width of 3x-4 and a length of 7x+3.
This is what I have:{{{ (3x-4)^2(7x+3)^2)}}}
I worked it this way:
(3x)^2-(4)^2 + (7x)^
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Question 843467: Find the area of a rectangle with a width of 3x-4 and a length of 7x+3.
This is what I have:
I worked it this way:
(3x)^2-(4)^2 + (7x)^2 + 3^2
9x+16+49x+9
58x+25
x= -33
Is this correct or where am I making my mistake? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! hi there,
Area of rectangle = length * width
Area of rectangle = (7x + 3)*(3x - 4)
Area of rectangle = 21x^2 - 28x + 9x - 12
Area of rectangle = 21x^2 - 19x - 12
You cannot find an answer for x unless you are given the actual area.
Hope this helps.
:-)
