SOLUTION: The perimeter of a playground is 504 and 2/3 yards. The length is 6 yards shorter than twice the width. What is the area of the playground?
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Question 842202: The perimeter of a playground is 504 and 2/3 yards. The length is 6 yards shorter than twice the width. What is the area of the playground? Answer by LinnW(1048) (Show Source):
You can put this solution on YOUR website! set L = length
W = width
L = 2W -6
L*W = 504 2/3
L*W = 1514/3
substitute 2W -6 for L
(2W -6)(W) = 1514/3
2W^2 -6W = 1514/3
add - 1514/3 to each side
2W^2 -6W - 1514/3 = 0
multiply by 3
6W^2 -18W -1514 = 0
W = (1/6)*(9+sqrt(9165))
W = (1/6)*(9-sqrt(9165)) , but this number is negative so does not work.
L =
