SOLUTION: I have been searching this site for hours for a solution to this: The rectangular cross-sectional area of a metal brace is to have an area of 2250 square millimeters. The length

Algebra ->  Rectangles -> SOLUTION: I have been searching this site for hours for a solution to this: The rectangular cross-sectional area of a metal brace is to have an area of 2250 square millimeters. The length      Log On


   



Question 841849: I have been searching this site for hours for a solution to this:
The rectangular cross-sectional area of a metal brace is to have an area of 2250
square millimeters. The length is to be one and one half times the width. Compute the length and width dimensions to the nearest millimeter. I am in
desperate need of an answer! Thank you.

Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
Set L = length , W = width
L = 1.5*W
area = L*W
2250 = L*W
substitute 1.5W for L
2250 = (1.5W)(W)
2250+=+1.5W%5E2
divide each side by 1.5
1500+=+W%5E2
W+=+sqrt%281500%29, approximately 38.73
L=+1.5sqrt%281500%29, approximately 58.02