Question 84091: The area of a rectangle of length x is given by 3x^2+5x. Find the width of the rectangle. How do I do this? Found 2 solutions by checkley75, ankor@dixie-net.com:Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! AREA OF A RECTANGLE=SIDE1*SIDE2. SO WE NEED TO FACTOR THIS ANSWER INTO 2 PARTS SIDE1 & SIDE2 THUS:
3X^2+5X
X(3X+5) X BEING SIDE 1 THEN (3X+5) IS SIDE2.
You can put this solution on YOUR website! The area of a rectangle of length x is given by 3x^2+5x. Find the width of the rectangle. How do I do this?
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You know that:
L * W = A
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In this problem; L is given as x and A is give (3x^2 + 5x); so we have:
x * W = 3x^2 + 5x
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Divide both sides by x:
W =
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Divide both terms by x and you have:
W = 3x + 5; is the width
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Check: L * W would be x*(3x+5) = 3x^2 + 5x which is given as the area
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