SOLUTION: The length of a rectangle is 3cm more than twice the width. If the perimeter is 90cm, what are its dimensions? Can you tell me how to write a system for that question?

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 3cm more than twice the width. If the perimeter is 90cm, what are its dimensions? Can you tell me how to write a system for that question?      Log On


   



Question 840108: The length of a rectangle is 3cm more than twice the width. If the perimeter is 90cm, what are its dimensions? Can you tell me how to write a system for that question?
Answer by isma95fb(6) About Me  (Show Source):
You can put this solution on YOUR website!
First write the data given in a proper format
let L = length, W = width
L - 2W = 3cm
L = 3cm + 2W
but perimeter = 2L + 2W
90cm = 2( 3cm + 2W) + 2W
90cm = 6cm + 5W
W = 16.8cm
and L = 3cm + ( 2 x 16.8)
L = 36.6cm