SOLUTION: The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is 58 feet. Find the width of the rectangle. I don't quite get these so far I got 2w + 2

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is 58 feet. Find the width of the rectangle. I don't quite get these so far I got 2w + 2      Log On


   

Question 835357: The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is 58 feet. Find the width of the rectangle.
I don't quite get these so far I got 2w + 2l = 58.
Help?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w for width
L for Length

highlight_green%28L=w%2B5%29; and highlight_green%282w%2B2L=58%29.
NOW can you see how to continue? The first sentence gave you the equation for L equals something.