SOLUTION: The perimeter of a rectangle is 46 feet. The width is 3ft. less than twice the length. Find the length and the width of the rectangle.
P=2L+2W
46=2L+2(2L-3)
46=2L+4L-6
52=6
Algebra ->
Rectangles
-> SOLUTION: The perimeter of a rectangle is 46 feet. The width is 3ft. less than twice the length. Find the length and the width of the rectangle.
P=2L+2W
46=2L+2(2L-3)
46=2L+4L-6
52=6
Log On
Question 833950: The perimeter of a rectangle is 46 feet. The width is 3ft. less than twice the length. Find the length and the width of the rectangle.
P=2L+2W
46=2L+2(2L-3)
46=2L+4L-6
52=6L
L=8.66
46=2(8.66)+2(2(8.66)-3)
46=17.32+2(17.32-3)
46=17.32+2(14.32)
46=17.32+28.64
46=45.96 ft.
L=8.66 ft. W=14.32 ft.
I'm not sure if this is correct since I kept getting decimals.
Thanks!!!
