SOLUTION: the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the length is 70 yards more then the width

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Question 832620: the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the length is 70 yards more then the width
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter is the fence around. It requires 2 pieces of length & 2 pieces of width. P = 2L + 2W
The question gives the following information:
700 = 2L + 2W
L = 70 + W
.
We can plug in the known values and then solve for W
700 = 2L + 2W
700 = 2(70+W) + 2W
700 = 140+2W + 2W
700 = 140 + 4W
700-140 = 4W
560 = 4W
560/4 = W
140 = W
.
If the width is 140 and the length is 70 more than that, then the length is 140+70 = 210
Let's make certain by adding these
2(140) + 2(210) = 700
280 + 420 does indeed = 700
Success!