SOLUTION: (1/2) Find the length and width of a rectangle the perimeter is 80m. The length is 4 times the width. Okay so what would the eqution be
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Question 832311: (1/2) Find the length and width of a rectangle the perimeter is 80m. The length is 4 times the width. Okay so what would the eqution be Answer by LinnW(1048) (Show Source):
You can put this solution on YOUR website! 2W + 2L = P where W is width, L is length and P is perimeter
L = 4W Substitute 4W for L and 80 for P
2W + 2(4W) = 80
2W + 8W = 80
10W = 80
W = 8
L = 4W = 4(8) = 32
