SOLUTION: the length of a rectangle is greater than its width by 4 cm. if the perimeter of the rectangle is 80 ' FIND THE SIDES OF THE RECTANGLE.

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Question 830868: the length of a rectangle is greater than its width by 4 cm. if the perimeter of the rectangle is 80 ' FIND THE SIDES OF THE RECTANGLE.

Found 2 solutions by JulietG, stanbon:
Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website!
The perimeter is a fence around. It requires 2 lengths of fence + 2 widths of fence. (P = 2L + 2W)
You're given the following information:
P = 80
L = W + 4
Substitute the value for L in the original equation:
P (80) = 2(W+4) + 2W
Distribute
80 = 2W + 8 + 2W
Add the Ws
80 = 4W + 8
Subtract 8 from each side
72 = 4W
Divide each side by 4
18 = W
.
Since you know the width is 18, you can find the length by adding 4. 18+4=22
Let's make certain by putting in the values:
2(22) + 2(18) = 80
44 + 36 does indeed equal 80.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
the length of a rectangle is greater than its width by 4 cm. if the perimeter of the rectangle is 80 ' FIND THE SIDES OF THE RECTANGLE.
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P = 2(L + W)
80 = 2(W+4 + W)
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40 = 2W+4
2W = 36
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Width = 18 cm
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Length = W+4 = 22 cm
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Cheers,
Stan H.
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