SOLUTION: The perimeter of a rectangle is 86cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
This is what I did so far ; w=width l=length
2w=L
2
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Rectangles
-> SOLUTION: The perimeter of a rectangle is 86cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
This is what I did so far ; w=width l=length
2w=L
2
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Question 830548: The perimeter of a rectangle is 86cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
This is what I did so far ; w=width l=length
2w=L
2L+2w=86
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2w=L>>> 2(2w)+2w=86
4w+2w=86
6w=86
6w/6w>>cancels out
86/6=14.3
w=14.3
from there is where I get confused because it makes no sense to me
Can you please help me solve this problem?....
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