SOLUTION: The length of a rectangle is 5 in longer than its width. If the perimeter of the rectangle is 42 in, find its area.

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Question 830442: The length of a rectangle is 5 in longer than its width.
If the perimeter of the rectangle is 42 in, find its area.
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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x = y + 5
2x + 2y = 42
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put the system of linear equations into standard form:
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x - y = 5
2x + 2y = 42
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solution:
x = 13 in
y = 8 in
area = 8*13 = 104 sq.in
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