SOLUTION: the perimeter of a rectangle is 58 centimeters. The length of the rectangle is four less than twice the width of the rectangle. what is length the width and area?
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Question 828433: the perimeter of a rectangle is 58 centimeters. The length of the rectangle is four less than twice the width of the rectangle. what is length the width and area? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! ---
2x + 2y = 58
x = 2y - 4
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put the system of linear equations into standard form:
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2x + 2y = 58
x - 2y = -4
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 18 cm
y = 11 cm
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system matrix
2 2
1 -2
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inverse of system matrix
0.33333333 0.33333333
0.16666667 -0.33333333
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determinant of system matrix = -6
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