SOLUTION: The perimeter of a rectangle is 58 centimeters . The length of the rectangle is four less than twice the width of the rectangle. Find the length, the width, and the area of this re

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 58 centimeters . The length of the rectangle is four less than twice the width of the rectangle. Find the length, the width, and the area of this re      Log On


   

Question 828324: The perimeter of a rectangle is 58 centimeters . The length of the rectangle is four less than twice the width of the rectangle. Find the length, the width, and the area of this rectangle.
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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2x + 2y = 58
x = 2y - 4
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put the system of linear equations into standard form:
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2x + 2y = 58
x - 2y = -4
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copy and paste the above linear system in standard form into this matrix-method solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x length = 18 cm
y width = 11 cm
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system matrix
2 2
1 -2
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inverse of system matrix
0.33333333 0.33333333
0.16666667 -0.33333333
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determinant of system matrix = -6
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Solve systems of linear equations up to 6-equations 6-variables:
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